One mole of propane is mixed with five moles of oxygen. The mixture is ignited and the propane burns completely. What is the volume of the products at s.t.p?
(G.M.V = 22.4 dm3 mol-1)
112.0 dm3
67.2 dm3
56.0 dm3
44.8 dm3
Explanation
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Discussions (8)

First, write out the balanced chemical equation:
C3H8 + 5O2 — 3CO2 + 4H2O
AT S.T.P (0°C):
*Water is a solid
* One mole of a gas is = 22.4dm³
Therefore, volume of 3 moles of CO2 is 3×22.4= 67.2dm³.
Water is a solid at standard temperature (0°C), and 4 moles of solid water has a negligible volume.

Pls someone should help me and solve it so dat I will understand better pls am confused

at standard temperature and pressure the temperature is 273 Kelvin which is the same thing as 0°.so at standard temperature and pressure the water will turn to liquid.

The question is wrongly composed:
The question says one mole of propane mixed with five moles of propane and not oxygen so please correct the question


