One mole of propane is mixed with five moles of oxygen. The mixture is ignited and the propane burns completely. What is the volume of the products at s.t.p?

(G.M.V = 22.4 dm3 mol-1)

a

112.0 dm3

b

67.2 dm3

c

56.0 dm3

d

44.8 dm3

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Correct Option
b

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Discussions (8)

biganimal
3 years ago

First, write out the balanced chemical equation:
C3H8 + 5O2 — 3CO2 + 4H2O

AT S.T.P (0°C):
*Water is a solid
* One mole of a gas is = 22.4dm³

Therefore, volume of 3 moles of CO2 is 3×22.4= 67.2dm³.

Water is a solid at standard temperature (0°C), and 4 moles of solid water has a negligible volume.

cuzi bounce
10 years ago

this is helping me to improve my studing

Chidimmchibuike
5 years ago

Pls someone should help me and solve it so dat I will understand better pls am confused

Paul78
1 year ago

at standard temperature and pressure the temperature is 273 Kelvin which is the same thing as 0°.so at standard temperature and pressure the water will turn to liquid.

De sage
1 year ago

CxHy+(x+y/4)O2--->xCO2+Y/2H2O

dubempowell
3 years ago

I don't understand this question

kenzuby10
10 years ago

The question is wrongly composed:

The question says one mole of propane mixed with five moles of propane and not oxygen so please correct the question

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