Given the reactions (i) Fe_(s) + X(NO₃)_2(aq) → Fe(NO₃) + X_(s) (ii) H_2(g) + XO → X + H₂O_(s); X is likely to be?

afahaidara

1 year ago

In reaction (i), Fe(s) (iron) is oxidized to Fe(NO3)2 (iron(II) nitrate), and X(NO3)2 (X(II) nitrate) is reduced to X(s) (element X).

This suggests that X is a metal that can be reduced by iron, and copper fits this description.

In reaction (ii), H2(g) (hydrogen gas) reduces XO (X(II) oxide) to X (element X) and H2O (water).

This reaction is consistent with copper(II) oxide (CuO) being reduced by hydrogen gas to form copper (Cu) and water:

CuO + H2 → Cu + H2O

The other options do not fit the reactions as well:

- B. Zinc is not typically reduced by iron.
- C. Calcium is not typically reduced by iron, and its oxide is not typically reduced by hydrogen gas.
- D. Lead is not typically reduced by iron.

Therefore, copper is the most likely candidate for X.

Chiamaka_2025

1 year ago

I don't understand the question

Akporute Onoriode

11 years ago

Yes since Fe nd H r higher dan Cu in d electrochemical series