What is the consequences of increasing pressure on the equilibrium reaction ZnO(s) + H2(g) Zn(s) + H2O(I)?
The equilibrium is driven to the left
The equilibrium is driven to the right
There is no effect
More ZnO is produced
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I dnt accept dat answer,presure affects the rxt bcos d principle says one f d product or reactant must be in gaseous form,one of d reactant is in gaseous form,therefore no f moles in reactant side is 1 nd product side 0,meanin increase in presure will cause d equilibrium pos shift 2 d product side where there is less no f moles.
please myschool help to do correction on this question, the correct option is B
Pressure is only applicable I gases
From the equation we have solids and liquids so pressure will have no effect on them
all of una self.
pressure only works on gases.
the only gases there is in reactant side but not in product side.
that means pressure won't have no effect on the reaction ok
Apologies please! Kindly note that the correction has been made. Thank you all for your contributions.
