acidified silver nitrate
acidified barium chloride
ime-water
dilute hydrochloric acid
acidified lead nitrate
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The characteristic test for any soluble tetraoxosulphate(VI) is the formation of white precipitate (barium sulphate) when a solution of barium chloride, acidified with dilute HCl, or when a solution of barium nitrate, acidified with dilute nitric acid is reacted with it.
BaCl2(aq) + H2SO4(aq) → 2HCl(aq) + BaSO4(s)
Ba(NO3)2(aq) + H2SO4(aq) → 2HNO3(aq) + BaSO4(s) - white precipitate
BaCl2 is used to tests for SO4²-, SO3²-, CO3²- and S²- . They all all react with BaCl2. But on addition of dil HCl all except BaSO4 gives a precipitate.
BaCl2 is used to test the presence of SO4²- but HCl confirms it.
Answer is D.
The correct answer for testing **Tetraoxosulphate (IV) ions**, also known as **sulfate ions (SO₄²⁻)**, is **B. acidified barium chloride**. When a solution of barium chloride is added to a solution containing sulfate ions and the solution is acidified with dilute hydrochloric acid, a white precipitate of barium sulfate (BaSO₄) forms. This is a characteristic test for the presence of sulfate ions.
The selected option is wrong!!!
When testing for ion, BaCl is the intermediate test while HCl will finalize the identity of SO4 ion,i hope myschool corrects this ASAP
