2MnO^-₄ + 10Cl^- + 16H⁺ → 2Mn²⁺ + 5Cl₂ + 8H₂O. Which of the substances serves as an oxidizing agent?

kayaboy2005

2 years ago

the Oxidizing agent will get it self reduced at the end of the reaction

thus MnO–⁴. is reduced to Mn

so D is legit

EzemaEbubechiKelvin7777

3 years ago

Oxidation can also be defined as the loss of electron so in the equation above mno4 loss two electron (2+)

Salah255

1 year ago

this questions was assually solve with Oxidation number

Salah255

1 year ago

The correct answer is B

Cl- is the only substance undergoing Reduction

and it is the oxidizing agent