A current of 10.0A was passed for 1 hour through a solution of copper (ll) sulphate between the copper electrodes. Which of the following observation would be correct?
(1 Faraday = 96,500 coulombs) (i) 0.186 mole of copper is dissolved from the anode. (ii) 0.372 mole of copper is deposited on the cathode. (iii) the original Cu2+ ion concentration of the solution remains unchanged. (iv) the original Cu2+ ion concentration of the solution decreases.
i and ii
i and iii
i and iv
ii and iii
ii and iv
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cu²+ +2e- ---- cu
from the reaction at the cathode
2f(moles of electron)------ 1mole of cu
Q=IT( 10×60×60)----------- will give xmol
2×96500-----1
36000 ----- x
x=36000/193000
x= 0.186mole.
the Answer is B
Note: the concentration of the copper ion remains unchanged because the electrodes are copper electrodes, so the amount of ions leaving the solution to be deposited on the cathode is equal to the amount of the ion entering the solution from the anode . The process is balance so the concentration of copper ions remain unchanged
The answer is B because the concentration of the solution remains unchanged during electrolysis of copper sulphate using COPPER electrodes. Rather it is the copper anode that loses electrons to form copper ion which then dissolves in the solution and migrates to the cathode to form copper solid by gaining two electrons and the cycle continues. As a result of this event the concentration of the copper sulphate solution remains unchanged. In conclusion the option C is wrong.
how can copper which carries a positive charge be deposited at the anode instead of the cathode
that is a mistake myschool option B is correct here is why
In the electrolysis of CuSO_4 with copper electrodes, the concentration remains unchanged. If it were platinum or carbon electrodes, then (iv) would be correct because the Cu^{2+} ions wouldn't be replaced.
Thank you all for your contributions. The necessary correction has been effected.
no. of moles= it/nF
I=10
t=60×60= 3600
n= Cu²+ (Copper is divalent)
F= 96500
= 3600×10/96500×2
= 36000/193000
=0.186.
For the "IV" I'm not really sure .🫥
