What quantity of electricity will liberate 0.125 mole of oxygen molecules during the electrolysis of dilute sodium chloride solution?
[ F = 96 5000 C mol-1 ]
24 125 coulombs
48 250 coulombs
72 375 coulombs
96 500 coulombs
Explanation
Video Explanation
No video available
Post your Contribution
Discussions (30)
n=m/M
m=n×M
M=16×2=32
m=0.125×32=4g
96500×2 ------------ 16g
96500×2×4/16 ------- 4g
48250 Columbus.
it says Oxygen molecules not oxygen gas. so it is not because oxygen is diatomic. it is 4 because in the electrolysis of dilute brine, the overall equation is
4OH+4H— 2H2O +2H2+O2
in the left and right hand side, molecules of oxygen is 4. i.e 4 moles of oxygen. thats why 4 is used
4 Farads will produce 1 mole of oxygen
Q Farads will produce 0.125 mole of oxygen
by cross multiplying, we have:
Q = 4 Farads = 4×965000
Remember, 1 Farad = 965000
so 4 Farads will be= 4×965000=3860000
therefore 3860000×0.125= 482500
guys the question says oxygen molecule and not its ion. if it is its ion, it should have been 4 Farads but since it is molecule, it should be 2 Farads which makes the answer to be A and not B pls.
since 1mol of o2 gives us 4F
then, 0.125 of o2 gives us ?
Ans=0.125*4*96500
=48,250.
The electrolysis of dilute sodium chloride solution produces hydrogen gas and oxygen gas at the electrodes. The balanced equation for the electrolysis of water is:
2H2O(l) → 2H2(g) + O2(g)
From this equation, we can see that 2 moles of hydrogen gas are produced for every 1 mole of oxygen gas. Therefore, if 0.125 moles of oxygen gas is produced, then 0.25 moles of hydrogen gas is also produced.
The quantity of electricity required to liberate a certain amount of a substance during electrolysis can be calculated using Faraday's law:
Q = nF
Where Q is the quantity of electricity in coulombs, n is the number of moles of the substance, and F is the Faraday constant (which is equal to 96,500 C/mol).
For the electrolysis of dilute sodium chloride solution, the sodium and chloride ions are also involved in the reaction. However, since we only want to find the quantity of electricity required to liberate oxygen gas, we can ignore the other ions.
Therefore, the quantity of electricity required to liberate 0.125 moles of oxygen gas is:
Q = nF = (0.125 mol)(2 mol O2/mol)(96,500 C/mol) = 24,125 coulombs
So the answer is A. 24,125 coulombs.
OR...
[1F = 96500, Valency of oxygen is 4. V = 0.125]
We all know that V=mol×Q/1F×Valency
Now in this case why mol is normally used is if u were given 22.40 at stp but we were not so..
V=Q/1F × Valency
In faradays law valency of oxygen is 4
So make Q subject of formular
THEREFORE
Q=V × 1F × Valency
Q=0.125 × 96500 × 4
Q = 48250 coulombs
The balanced chemical equation for the electrolysis of dilute sodium chloride solution is:
2H2O(l) → 2H2(g) + O2(g)
From the equation, it can be seen that for every mole of O2(g) produced, 4 moles of electrons (4e-) are transferred. Therefore, the number of moles of electrons required to liberate 0.125 moles of O2 is:
4 mol e- / 1 mol O2 × 0.125 mol O2 = 0.5 mol e-
The quantity of electricity (Q) required to transfer 0.5 moles of electrons can be calculated using Faraday's constant (F) as:
Q = n × F
where n is the number of moles of electrons transferred.
Substituting the values, we get:
Q = 0.5 mol × 96 500 C/mol = 48 250 C
Therefore, the answer is option B: 48 250 coulombs.
In the electrolysis of dilute NaCl:
NaCl → Na⁺ + Cl⁻
H₂O → H⁺ + OH⁻
at Cathode: 4H⁺ + 4e⁻ → 2H₂
at Anode: 4OH⁻ → 2H₂O + O₂ + 4e⁻
Here, 4 moles of electron yield 1 mole of oxygen gas
4e⁻ ≡ O₂
4 x 96500 ≡ 1 mol (of O₂) (since 1F = 96500C)
Let y = quantity of electricity (required)
386000 ≡ 1 mol (of O₂)
y ≡ 0.125 (of O₂)
by cross multiplying
y x 1 = 386000 x 0.125
y = 48250C
@vykhy...all gases are diatomic....so the valencey of oxygen was multiplied by 2 to give 4 moles of oxygen
o2+4e=o
1 mole-----4x96500
0.125mole-----x
cross multiply
0.125 x 4 x 96500
=48250
