5cm3 of a saturated solution of sodium chloride at 30°C gave, on careful evaporation, 1.95g of solid salt. The solubility of sodium chloride at 30°C?
(Na = 23, Cl = 35.5)
a
5.00 mole dm3
b
5.67 mole dm3
c
6.00 mole dm3
d
6.67 mole dm3
e
7.00 mole dm3
Explanation
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Discussions (8)

Pacifica
3 years ago
You can use this formula
Solute/solvent X 1000/molar mass
1.95/5 X 1000/58.5
=6.67mol dm³

Rubyn
1 year ago
solubility= mass/molar mass multipled by 1000/volume
while we have a mass of 1.95g and a molar mass of 58.5(23+35.5), volume of 5cm³
therefore 1.95/58.5 × 1000/5
=0.03×200
=6.67dm³~

Anela
1 year ago
oh!
God bless y'all for a quick reminder of this formula.🤗
Compared to that stuff they were solving there

Pacifica
3 years ago
You can use this formula
Solubility=solute. 1000
------------ X -----------
Solvent. Molar mass


