28.8 cm³ of nitrogen at 15°C is cooled to O°C at constant pressure, the new volume of nitrogen is?

Nkiru555

1 year ago

V1T2=V2T1 and (remember all temperatures must be in kelvin , if it is not, add 273 to the given temp)
V1=28.8 , T2=0°c+273=273k , V2=?, T1=15°c+273=288k .
substitute in V1T2=V2T1
28.8×273k=V2×288k
V2=27.3cm^3

Peternovich7

5 years ago

Where is 288 coming from
Na 28.8 det there na

Bel1762023

3 years ago

Charles law v1/t1=v2/t2
T1=15+273=288(i.e standard temp)always add
T2=0+273=273
V1=28.8
V2=?
Cross multiply ... V2=v1t2÷t1
V2=28.8×273/288
=27.3cm3

Longe Peace

12 years ago

not clear