N\(_2\)O\(_4\)(g) ↔ 2NO\(_2\)(g). Increase in total pressure of the equilibrium reaction above will

a

produce more of NO2(g) in the mixture

b

convert all of N2O4(g) to NO2(g)

c

have no effect on the concentrations of NO2(g)and N2O4(g)

d

produce more of N2O4(g) in the mixture

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Explanation

Correct Option
d

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Discussions (10)

MAGISTER
9 years ago

Here is an explanation:

pressure affects a reversible reaction if the reactants & products are gaseous as in this case.There are 2volumes of NO &1volume of N2O4 HENCE THE REACTION PROCEEDS WITH AN INCREASE IN VOLUME.if the pressure is increased,the volume have to reduce since both are inversely proportional. the reaction that does this is the backward reaction which proceeds with a reduction in volume.more of N2O4 in the equilibrium mixture.

dominic12
13 years ago

d is correct bcos increase in pressure helps d lowest num of mole which is nitrogen iv oxide

onwosiiyk
12 years ago

Yes option D is correct because at any time pressure increases the concentration will decrease and verse versa in accordance with the Le' chatellier principle.

AnthonyAgofure
3 years ago

i agree wity y'all

amaechi unya
13 years ago

D is rit increase in presure leads to increase in nitrogen iv oxide

PCE
3 years ago

The equilibrium reaction N2O4(g) ↔ 2NO2(g) involves a change in the number of moles of gas particles, since there are two moles of gas on the right-hand side of the equation and one mole of gas on the left-hand side. Therefore, a change in pressure will affect the equilibrium position of the reaction.

According to Le Chatelier's principle, an increase in total pressure will cause the equilibrium to shift in the direction that produces fewer moles of gas. In this case, since there are fewer moles of gas on the left-hand side of the equation, the equilibrium will shift towards that side, producing more N2O4(g).

Therefore, the correct answer is D. An increase in total pressure will produce more of N2O4(g) in the mixture.

pascal5050
1 year ago

why no explanation

John00777
2 years ago

The correct answer is C! 🌪️

To understand why this is the case, we need to know a bit about Le Chatelier's Principle. This principle states that if a system in equilibrium is disturbed, the system adjusts to reduce that disturbance.

In this case, the pressure of the system is increased, but the number of moles of gas is unchanged. Since both N2O4 and NO2 are gases, an increase in pressure has no effect on the concentrations of these gases.

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