If the rate of diffusion of oxygen gas is taken as 1, what will be rated of diffusion of methane whose relative molar mass is 16?

odun@nice

12 years ago

The rate of diffusion of a gas is inversly proportional to the square root of it vapour density. 1/X=root 16/32 square both side =(1/X)square =1/2 =X square =2 and x=root 2, x= 1.414

kamsi

11 years ago

thanks alot

oluogun

1 year ago

oxygen is 32 because the atomic mass of oxygen is 16.since oxygen is always written as O2.They multiply the 2 by 16 to make 32

Newton2i

2 years ago

that first guy is dam right all this baba na rubbish una dey yarn

VictorAgulonu

1 year ago

According to Graham's Law of Diffusion, the rate of diffusion of a gas is inversely proportional to the square root of its molar mass. Mathematically, this can be expressed as: $\qquad \frac{Rate_1}{Rate_2} = \sqrt{\frac{M_2}{M_1}}$ Where: * $Rate_1$ is the rate of diffusion of gas 1. * $Rate_2$ is the rate of diffusion of gas 2. * $M_1$ is the molar mass of gas 1. * $M_2$ is the molar mass of gas 2. In this problem, we are given: * $Rate_1$ (oxygen) = 1 * $M_1$ (oxygen, $O_2$) = 32 g/mol * $M_2$ (methane, $CH_4$) = 16 g/mol We want to find $Rate_2$ (methane). Plugging the values into Graham's Law: $\qquad \frac{1}{Rate_2} = \sqrt{\frac{16}{32}}$ $\qquad \frac{1}{Rate_2} = \sqrt{\frac{1}{2}}$ $\qquad \frac{1}{Rate_2} = \frac{1}{\sqrt{2}}$ $\qquad Rate_2 = \sqrt{2}$ $\qquad Rate_2 \approx 1.414$ Therefore, the rate of diffusion of methane is approximately 1.4. The correct answer is C.

Bhabz206

2 years ago

pls how come oxygen is 32

Bankybenz

3 years ago

my school the answer is 0.5 oh

Som15432

1 year ago

Here's how to figure that out:
* Graham's Law of Diffusion: This law tells us that the rate of diffusion of a gas is inversely proportional to the square root of its molar mass. In simpler terms, lighter gases diffuse faster than heavier gases.
* Oxygen's Molar Mass: Oxygen (O₂) has a molar mass of approximately 32.
* Methane's Molar Mass: Methane (CH₄) has a molar mass of 16.
To find the relative diffusion rate of methane compared to oxygen, we can use this formula:
Rate of diffusion of methane / Rate of diffusion of oxygen = √(Molar mass of oxygen / Molar mass of methane)
So, in this case:
Rate of diffusion of methane / 1 = √(32 / 16)
Rate of diffusion of methane = √2
Rate of diffusion of methane = approximately 1.4
Therefore, the answer is C. 1.4.

Obehs

4 years ago

Answer should be 0.5

Obehs

4 years ago

Answer is D. Because rate of diffusion is is inversely proportional to molar mass. That is 1/x=√16/√16