1.00 g of the oxide of metal X (atomic mass = 64) gave 0.80 g of the metal when reduced with hydrogen.
The formula of the oxide is?
X2O
XO
XO2
X2O3
X3O4
Explanation
No explanation available
Video Explanation
No video available
Post your Contribution
Discussions (14)

Datas Given from the question:
- Mass of oxide of the metal = 1g
- Atomic mass of the metal = 64g
- Mass of the metal on reduction with hydrogen = 0.8g
Therefore; mass of the oxide = mass of oxide of metal - mass of metal = 1 - 0.8 = 0.2g
To find the Empirical formula,
x. 0
0.8 0.2
divide each by it's atomic mass
0.8/64 = 0.0125 0.2/16= 0.0125
divide each by the smallest number
0.0125/0.0125 = 1 0.0125/0.0125 =1
Therefore, the formula of the of the metallic oxide

Short Method:
1. Mass of metal = 0.80 g
2. Atomic mass = 64
→ Moles of metal = 0.80 ÷ 64 = 0.0125 mol
3. Mass of oxygen = 1.00 − 0.80 = 0.20 g
→ Moles of oxygen = 0.20 ÷ 16 = 0.0125 mol
4. Ratio = Metal : Oxygen = 0.0125 : 0.0125 = 1 : 1
Answer: XO

Just know that is copper from the atomic number given and we know that the most stable oxidation state of copper is 2

Short Method:
1. Mass of metal = 0.80 g
2. Atomic mass = 64
→ Moles of metal = 0.80 ÷ 64 = 0.0125 mol
3. Mass of oxygen = 1.00 − 0.80 = 0.20 g
→ Moles of oxygen = 0.20 ÷ 16 = 0.0125 mol
4. Ratio = Metal : Oxygen = 0.0125 : 0.0125 = 1 : 1
Answer: XO

To find the formula of the oxide, we need to determine the molar ratio of metal X to oxygen in the oxide.
Calculate the number of moles of metal X produced:
Molar mass of metal X
=
64
g/mol
Molar mass of metal X=64g/mol
Mass of metal X produced
=
0.80
g
Mass of metal X produced=0.80g
Number of moles of metal X
=
Mass
Molar mass
=
0.80
g
64
g/mol
=
0.0125
mol
Number of moles of metal X=
Molar mass
Mass
=
64g/mol
0.80g
=0.0125mol
Since the oxide of metal X produces 0.80 g of metal X, the remaining mass is due to oxygen:
Mass of oxygen
=
1.00
g
−
0.80
g
=
0.20
g
Mass of oxygen=1.00g−0.80g=0.20g
Calculate the number of moles of oxygen:
Molar mass of oxygen
=
16
g/mol
Molar mass of oxygen=16g/mol
Number of moles of oxygen
=
Mass
Molar mass
=
0.20
g
16
g/mol
=
0.0125
mol
Number of moles of oxygen=
Molar mass
Mass
=
16g/mol
0.20g
=0.0125mol
Determine the mole ratio of metal X to oxygen:
Metal X
:
Oxygen
=
0.0125
mol
:
0.0125
mol
Metal X:Oxygen=0.0125mol:0.0125mol
From the mole ratio, we can see that the formula of the oxide is XO.
So, the correct answer is B. XO.



