2SO2(g) + O2(g) ↔ 2SO3(g). In the chemical reaction above, the substance that will increase the rate of production of sulphur (VI) oxide is
manganese (IV) oxide
finely divided iron
vanadium (V) oxide
nickel
Explanation
No explanation available
Video Explanation
No video available
Post your Contribution
Discussions (11)
The equation above is called contact process. Contact process is used to produce sulphuric acid.
The catalyst used for this reaction is vandanium V oxide
C is correct 😊
It's the catalyst use, a catalyst increases the rate of chemical reaction by lowering the activation energy
vanadium v oxide increases its productn and makes it faster and simple during de productn of SO2
Why not other catalysts, or is it specified for the production of SO3 only ?
The chemical equation given represents the formation of sulfur trioxide (SO3) from sulfur dioxide (SO2) and oxygen (O2). The forward reaction will result in an increase in the amount of SO3 produced, while the reverse reaction will decrease the amount of SO3 produced.
To increase the rate of production of SO3, a catalyst can be added. A catalyst is a substance that increases the rate of a chemical reaction without being consumed in the reaction itself.
Out of the options given, the most commonly used catalyst for this reaction is vanadium (V) oxide (V2O5), which is option C. Therefore, the correct answer is C, vanadium (V) oxide.
