How many structural isomers can be drawn for the non-cyclic alkanol with molecular formula C 4H10O?
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Okay! Let's break down how to figure out the structural isomers of C4H10O, focusing on the alkanol (alcohol) part. That means we're looking for structures with an -OH group.
Here's how we can approach it:
* Understanding Isomers:
* Structural isomers have the same molecular formula (C4H10O) but different arrangements of atoms.
* Since we are focusing on Alkanols, we are looking for the possible ways that the OH group can be placed on a 4 carbon chain.
* Possible Alcohol Structures:
* We'll start with a straight chain of four carbons:
* Butan-1-ol: The -OH group is on the first carbon.
* Butan-2-ol: The -OH group is on the second carbon.
* Now, let's consider branched chains:
* 2-methylpropan-1-ol: A three-carbon chain with a methyl group (CH3) on the second carbon and the -OH on the first carbon.
* 2-methylpropan-2-ol: A three-carbon chain with a methyl group on the second carbon and the -OH on the second carbon.
* The Answer
* Therefore there are 4 structural isomers of the non-cyclic alkanol with the molecular formula C4H10O.
I hope this helps!
Butan-1-ol, butan-2-ol, 2-methylpropane-1-ol, 2-methylpropane-2-ol --4 The answer is correct !
I dont agree with the Humanoid's answer parent Hydrocarbon where other Hydrocarbons derive their structure(alkyl group) is the Alkane homologue. Since Butane which is an alkane with the molecular formula as C4H10 then the Butanoic acid should have 2 Iso-Butanoic structure.
