The solubility product of Cu(IO3)2 is 1.08 * 10-7. Assuming that neither ions react appreciable with water to form H+ and OH-, what is the solubility of this salt?
2.7 * 10-8 mol dm-3
9.0 * 10-8 mol dm-3
3.0 * 10-3 mol dm-3
9.0 * 10-3 mol dm-3
Explanation
Video Explanation
No video available
Post your Contribution
Discussions (41)
If u see questions like this u have no option than to cram it.that is the only seceat advice
Ksp=(x)(x). 1.08*10^7=(2x)^2(x). 1.08*10^-7=4x^3. x^3=1.08*10^-7/4. x^3=0.27*10^-7 x^3=27*10^-9 x=cubic root of 27*10^-9 x=3*10^-3 C is d correct ans
Please, clarify yourself and may I know where all the values came from @Ola1000
Ksp=(x)(x). 1.08*10^7=(2x)^2(x). 1.08*10^-7=4x^3. x^3=1.08*10^-7/4. x^3=0.27*10^-7 x^3=27*10^-9 x=cubic root of 27*10^-9 x=3*10^-3 C is d correct ans
Thank you all for your contributions. The necessary correction has been effected
