The solubility product of Cu(IO3)2 is 1.08 * 10-7. Assuming that neither ions react appreciable...

JAMB 1999

The solubility product of Cu(IO₃)₂ is 1.08 * 10^-7. Assuming that neither ions react appreciable with water to form H⁺ and OH^-, what is the solubility of this salt?

A. 2.7 * 10^-8 mol dm^-3
B. 9.0 * 10^-8 mol dm^-3
C. 3.0 * 10^-3 mol dm^-3
D. 9.0 * 10^-3 mol dm^-3

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Correct Answer: Option D

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