The solubility product of Cu(IO3)2 is 1.08 * 10-7. Assuming that neither ions react appreciable...

JAMB 1999

The solubility product of Cu(IO₃)₂ is 1.08 * 10^-7. Assuming that neither ions react appreciable with water to form H⁺ and OH^-, what is the solubility of this salt?

A. 2.7 * 10^-8 mol dm^-3
B. 9.0 * 10^-8 mol dm^-3
C. 3.0 * 10^-3 mol dm^-3
D. 9.0 * 10^-3 mol dm^-3

WAEC May/June 2024 - Practice for Objective & Theory - From 1988 till date, download app now - 99995

WAEC offline past questions - with all answers and explanations in one app - Download for free

Post-UTME Past Questions - Original materials are available here - Download PDF for your school of choice + 1 year SMS alerts

Correct Answer: Option D

Explanation

No official explanation is available for this question at this time. Please check contributions posted by others below. If you can provide an explanation to help other student learn, please click here

Previous Next

Go back to Chem classroom

Report an Error Ask A Question Download App