The pH of a solution obtained by mixing 100cm\(^3\) of a 0.1M HCl solution with 100cm\(^3\) of a 0.2M solution of NaOH is?
1.3
7.0
9.7
12.7
Explanation
Video Explanation
No video available
Post your Contribution
Discussions (30)
100/1000×0.2/1=0.02moles
pH=-log(2×10-²)
log2=0.3
-log10(10^0.3×10^-²)
-log10(10^-1.698)
=-(-1.698)= 1.698
pH+pOH=14
1.698+pOH=14
pOH=14-1.698=12.3
this is the closest i can get
OR
antilog of 0.02=1.047
pOH=14-1.047=12.9
A is typically incorrect. How? Knowing fully well that NaOH is a strong base with increasing alkalinity.
B also can't be the right option. The pOH value is neutral.
Your options is in between C and D which are all alkaline in nature. You've got to choose wisely even before solving out the question.
Using the basic formulae:
pH + pOH = 14
no of moles = conc(moles/dm³) x vol./1000.
The complete question👇
The pH of a solution obtained by mixing 100cm³ of a 0.1M HCl solution with 100cm³ of a 0.2M solution of NaOH is ???
To determine the pH of the solution obtained by mixing 100 cm3 of a 0.2 M solution of NaOH, we need to consider the properties of NaOH and its reaction with water.
NaOH is a strong base that dissociates completely in water to form hydroxide ions (OH-) and sodium ions (Na+). The hydroxide ions are responsible for the basic nature of the solution.
When we mix NaOH with water, the concentration of hydroxide ions increases, leading to an increase in the pH of the solution. The pH scale ranges from 0 to 14, with 7 being neutral. A pH below 7 indicates acidity, while a pH above 7 indicates alkalinity or basicity.
In this case, since NaOH is a strong base, the resulting solution will be basic. Therefore, the correct answer is option D. The pH of the solution obtained by mixing 100 cm3 of a 0.2 M solution of NaOH is approximately 12.7.
The question should be
The pH of a solution obtained by mixing 100cm³of a 0.2M solution of NaOH is??
Apologies! Thank you all for your contributions. Kindly note that the necessary correction has been made and the explanation (solvings) available in the explanation box above.
Thanks.
Well from how I best understand the question NaOH is a base so you when you mix 100cm of 0.2 mol solution the alkalinity would increase and the value with the highest alkaline there is d...I hope this helps
