90.0g of MgCI₂ was placed in 50.0cm³ of water to give a saturated solubility of the salt is 8.0 mol dm³ at the same temperature, what is the mass of the salt left undissolved at the given temperature?

(Mg = 24, Cl = 35.5)

olyezema

4 years ago

n=C×V/1000
n=m/M
m/M=C×V/1000
m=C×V×M/1000
M=24+35.5×2=95g
m= 8×50×95/1000
m=38g
mass of salt left undissolved
m=90-38=52g

aplutocrat

8 years ago

There is an error in the question, instead of writing 8mol per dm cube they put 80 mole perdm cube

millionaire001

1 year ago

video lesson attached to correction