Chemistry jamb 1998

C3H8(g) + 502(g) → 4H2O + 3CO2(g). Form the equation above the volume of oxygen at s.t.p. required to burn 50cm3 of propane is?

a

250 cm3

b

150 cm3

c

100 cm 3

d

50 cm3

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a

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djayenimoney
4 years ago

The mole ratio of propane to oxygen I'd 1:5
Therefore is 1-------->5
Then 50-------->x
x=5*50=250 cm³

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