C3H8(g) + 502(g) → 4H2O + 3CO2(g). Form the equation above the volume of oxygen...

JAMB 1998

C₃H_8(g) + 50_2(g) → 4H₂O + 3CO_2(g). Form the equation above the volume of oxygen at s.t.p. required to burn 50cm³ of propane is?

A. 250 cm³
B. 150 cm³
C. 100 cm ³
D. 50 cm³

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Correct Answer: Option A

Explanation

C₃H₈ + 50₂ → 4H₂O + 3CO₂.
From the equation above 1 dm³ of C₃H₈ require 5dm³ of O₂ at s.t.p.
∴ 50cm³ of C₃H₈ require x = (50) / (1000) x 5 x 1
x = (250) / (1000)
x = 250cm

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C3H8(g) + 502(g) → 4H2O + 3CO2(g). Form the equation above the volume of oxygen...

Correct Answer: Option A

Explanation

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