A given amount of gas occupies 10.0 dm3 at 4atm and 273°C. The number of moles of the gas present is?
(Molar volume of a gas at s.t.p. = 22.4 dm3)

Maugo727

6 years ago

Ideal gas equation.
Pv=nrt
Where P = 4 atm, V = 10 dm^3 , r = 0.082 T= 273+273 > 546 n = ?..
Make n subject of the formula
n = PV/rT
n = 4 × 10÷ 0.082 × 546
n = 40 ÷ 44.772
n = 0.89mole..

Lydwina

10 years ago

U cannot post a question dat doesn't hv answers, it doesn't make sense nah, it even discourages pple from continuing wit d CBT

Sagacity300

5 years ago

Using PV=nRT
T=273+273=546k
n=pv/RT=4*10/0.082*546=0.89mole

Aghepromise

7 years ago

Pls, somebody shud explain how i can solve this question.

Opeyemi1234

12 years ago

Dis Gud,It Improves Ur Knowledge Nd Speed Us Up

dojah123

3 years ago

mu school pls correct tye question 4atm is omitted

MRICHARD

1 year ago

correct answer

ronkebakare

2 years ago

The 273°C wasn’t changed to Kelvin and the answer is supposed to be 0.89

Jay -jay. west

11 years ago

Bros I hail!! Una 4 solve am na!

Dave333

4 years ago

In the question, pressure has 4atm.Eeemm....my school make correction

Ewe_pra

2 years ago

It is not complete

Lisamoore

4 years ago

the correct answer is 22.4mole