25 cm\(^3\) of 0.02 M KOH neutralized 0.03 g of a monobasic organic acid having the general formula C\(_n\)H\(_{2n + 1}\)COOH. The molecular formula of the acid is?

(C = 12, H = 1, O = 16)

olyezema

4 years ago

if you really understand what you are doing it won't take you any time just less than 2 minutes............you can also use the easiest method
n= C×V/1000
n= 0.02×25/1000
n=5×10-⁴moles
n=m/M
M=m/n
M=0.03/0.0005=60g
CnH2n+1COOH=60
12n+2n+1+12+16+16+1=60
14n+46=60
14n=60-46=14
n=14/14=1
CH3COOH---------C.

HRC2023

2 years ago

hey i must pass jamb

Prof E.C.G

12 years ago

Jamb wicked!..How many minutes una want make we spend 4dis kind qstns on the "D DAY"?

JACUZY

1 year ago

ur answers are confusing

Dami54

3 years ago

Thank you very much...u have common sense

NNAEMEKAPROMISE

1 year ago

please i am kind of confused, where is the 60 from

leonard0

11 years ago

i think the answer is B cos they used the conc of the base which was 0.78 instead of that of the acid which is 1.2 while finding for the RMM of the acid ... and after correcting and using the right values the answer turns out to be C2H5COOH