Unsaturated compounds like ethyne readily undergo addition reactions where a molecule adds across the double or triple bond.
Ethyne reacts with HI in a two-step process, with the first step forming an intermediate with a carbon-carbon double bond, and the second step forming the final product, 1,1-diiodoethane.
First step : H-C≡C-H + HI → H\(_2\)C=CHI
Second step: H\(_2\)C=CHI + HI → H\(_3\)C-CHI\(_2\)
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