Correct Answer: Option A

Explanation

Unsaturated compounds like ethyne readily undergo addition reactions where a molecule adds across the double or triple bond. 

Ethyne reacts with HI in a two-step process, with the first step forming an intermediate with a carbon-carbon double bond, and the second step forming the final product, 1,1-diiodoethane. 

         First step :          H-C≡C-H  +  HI  →  H\(_2\)C=CHI 

         Second step:      H\(_2\)C=CHI  +  HI →  H\(_3\)C-CHI\(_2\) 

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