The removal of rust from iron by treatment with tetraoxosulphate (IV) acid is based on the?
hydrolysis of the iron
reaction of acid with base
oxidationof the rust
dehydration of the iron
Explanation
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The correct answer is B...rust is a base which is neutralised by H2SO4, hence removal of rust is a neutralisation reaction
B is d correct answer . lets make use of another acid Hcl.
Fe2O3+ 6HCl> 2FeCl3(a salt) + 3H2O.
Hence the removal of rust with an acid is a neutralization(acid and base) reaction
The correct. Answer is C .acids remove rust by oxidation. Below are the reactions with proof
4H2SO4+2Fe2o3 --- 4Feso4+ 4H2o +o2
In the reaction above iron increased oxidation state from +2 to +6. Termed oxidation
If another acid is used, for same reaction?
Fe2o3 + 6Hcl--- 2fecl3 + 3H2o
Iron changed from +2 to +3 oxidation state. Termed oxidation..
The reaction is not neutralization because rust is only a basic oxide ( will only dissolve in water to produce the corresponding base) so it is not a base yet. But can play a function related to that.
Pls take note.
the answer should be B besides iron oxide in that form is iron III oxide and it gets reduced to iron Ii sulfate so definitely iron is reduced
The correct answer is C. The removal of rust from iron by treatment with tetraoxosulphate (IV) acid is based on the oxidation of the rust. The tetraoxosulphate (IV) acid acts as an oxidizing agent, and it oxidizes the rust on the iron to form iron (II) ions and water. The iron (II) ions then combine with the tetraoxosulphate (IV) ions to form iron (II) tetraoxosulphate (IV) complex ions¹.
The other options are incorrect because:
- A. Hydrolysis of the iron would mean that water breaks down the iron into hydrogen and iron (II) or iron (III) ions. This is not what happens when iron rusts or when it is treated with an acid.
- B. Reaction of acid with base would mean that the acid neutralizes the base and forms a salt and water. However, rust is not a base, but a mixture of iron oxides and hydroxides. It does not react with acids in a neutralization reaction, but in an oxidation-reduction reaction.
- D. Dehydration of the iron would mean that water is removed from the iron, leaving behind a dry iron oxide. This is not what happens when iron rusts or when it is treated with an acid.
All the answers are plausible, althoughl oxidation is the best answer.
Sulfuric acid is a strong oxidizing agent and reacts with rust (iron oxide) to convert it into soluble iron(II) sulfate, which can then be easily washed away. So, the process primarily involves the oxidation of the rust rather than hydrolysis of the iron, reaction of acid with base, or dehydration of the iron.
The correct answer is C! The removal of rust from iron by treatment with tetraoxosulphate (IV) acid is based on the oxidation of the rust. The tetraoxosulphate (IV) acid acts as an oxidizing agent, and it oxidizes the rust on the iron to form iron (II) ions and water. The iron (II) ions then combine with the tetraoxosulphate (IV) ions to form iron (II) tetraoxosulphate (IV) complex ions.
correct answer is B
Explanation: rust (iron III oxide) is an amphoteric oxide, it reacts with the acid to form salt and water, thereby removing the rust. Amphoteric oxide in the presence of acid acts as a base, it can also act as an acid in the presence of a base.
