2X(aq) + MnO2(s) + 4H+(aq) → X2(g) + Mn2+(aq) + 2H2O.
The reaction above can be used for the laboratory preparation of all halogens except fluorine because it is?

a

a poisionous gas

b

an oxidizing agent

c

electronegative in nature

d

highly reactive

Download Offline App Ask a Question

Explanation

Correct Option
d

No explanation available

Video Explanation

No video available

Post your Contribution

Share:

Discussions (2)

Great question! 🔥 This dives into some fascinating chemistry of the **halogens**, especially **fluorine** (F₂). Here's the key idea:

---

### 🧪 Why **fluorine** can’t be produced by oxidizing fluoride ions with MnO₂ (or similar oxidizing agents):

#### 1. **Fluoride ion (F⁻) is extremely stable**
- Fluorine has the **highest electronegativity** of all elements.
- That means it **strongly holds onto electrons**, making the **F⁻ ion very hard to oxidize** back to F₂.
- It's incredibly difficult to remove an electron from F⁻ — you need a **very strong oxidizing agent**, stronger than MnO₂.

#### 2. **Standard electrode potential (E°) is very high**
- The half-cell reaction for fluorine:
\[
\text{F}_2 + 2e^- \rightarrow 2\text{F}^-
\quad E^\circ = +2.87\,\text{V}
\]
- Compare this to chlorine:
\[
\text{Cl}_2 + 2e^- \rightarrow 2\text{Cl}^-
\quad E^\circ = +1.36\,\text{V}
\]

Because fluorine’s **reduction potential is so high**, the reverse (oxidizing F⁻ to F₂) is extremely difficult and requires a **more powerful oxidizer than MnO₂**, which is strong enough for Cl⁻ or Br⁻ but **not for F⁻**.

#### 3. **MnO₂ is not a strong enough oxidizer**
- MnO₂ can oxidize:
- **Cl⁻ → Cl₂**
- **Br⁻ → Br₂**
- **I⁻ → I₂**
- But **not F⁻ → F₂**, because the energy required is much higher.

---

### 🧪 How is fluorine actually produced then?
Fluorine is produced **electrochemically**, not chemically. The **Moissan process** is used:

\[
\text{Electrolysis of molten potassium fluoride (KF) in anhydrous HF}
\]

\[
\text{At anode:} \quad 2\text{F}^- \rightarrow \text{F}_2 + 2e^-
\]

This method bypasses chemical oxidizers and uses electricity to force the reaction.

---

### ✅ Summary:
- Fluoride ions are **too stable**.
- MnO₂ isn't strong enough to oxidize F⁻.
- Fluorine is only obtained by **electrolysis**, not chemical oxidation.

Let me know if you want a comparison chart with other halogens too!

DrAbba
1 year ago

sure

Quick Questions

Ask a Question
CO

ceoofwahala

20th June, 2026

Chemistry


2 comments

ASSAAS

20th June, 2026

English Language


5 comments

infinitehoaxx

21st May, 2026

Computer


4 comments