potasium dioxonitrate (III)
lead (IV) oxide
potassium trioxochlorate (V)
potassium trioxonitrate (V)
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The correct answer is **Option A**. Potassium dioxonitrate (III) or potassium nitrite (KNO2) does not produce oxygen on heating. Instead, it decomposes into potassium nitrate (KNO3) and nitrogen monoxide (NO) as shown by the following equation:
2KNO2 __∆__ KNO3 + NO
The other options are all oxygen-rich compounds that release oxygen gas on heating. For example, lead (IV) oxide (PbO2) decomposes into lead (II) oxide (PbO) and oxygen gas (O2) as shown by the following equation:
2PbO_2 __∆___ 2PbO + O2

there is no answer,cos they will all give up oxygen
Sure, let's balance the chemical equations for the given options:
A. Potassium dioxonitrate (III) - \(2KNO_2 \rightarrow 2KNO_3 + O_2\)
B. Lead (IV) oxide - \(2PbO_2 \rightarrow 2PbO + O_2\)
C. Potassium trioxochlorate (V) - \(2KClO_3 \rightarrow 2KCl + 3O_2\)
D. Potassium trioxonitrate (V) - \(2KNO_3 \rightarrow 2KNO_2 + O_2\)

They produce nitrogen (I) oxide and steam on decomposition
NH3NO2 ----- N2O + H2O

