2H2S(g) + SO2(g) + H2O(I) → 3S(s) + 3H2O(I)..........(i) 3CuO(s) + 2NH3(g) → 3Cu(s) + 3H2O(I) + N2(g).........(II) In the equations above, the oxidizing agent (I) and the reducing agent in (II) respectively are?
H2S and NH3
SO2 and CuO
SO2 and NH3
H2S and CuO
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oxidizing agents are subtanced or species that are REDUCED, while reducing agents are subtanced that are OXIDISED.
please note that the oxidizing and reducing agent can only come from the reactants side, this alone will help you eliminate some wrong answers in the option
H2S + SO2+ H2O----> S2 + 3H2O
If you look at the first equation, oxygen was removed from SO2 and removal of Oxygen is reduction so SO2 is the oxidizing agent because it was reduced, again oxidizing agent are subtanced that are reduced, they undergo reduction in the process of oxidizing another substance.
looking at the second equation
2CUO + 2NH3----->CU + 3H2O + N2
here too the answer is between CUO and NH3 even if you don't know the answer, you must know that the answer will only be on the reactants side and not on the product.
looking at NH3, Hydrogen was removed from it making it to turn to N2 and removal of Hydrogen is oxidation, meaning it undergo oxidation and reducing agent are subtanced that are oxidized.
So the oxidizing and reducing agents are SO2 and NH3 respectively.
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