The hydroxyl ion concentrated, (OH-), in a solution of sodium hydroxide of pH 10.0 is?

a

10-10 mol dm-3

b

10-6 mol dm-3

c

10-4 mol dm-3

d

10-2 mol dm-3

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Explanation

Correct Option
c

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Discussions (14)

P.blessed
10 years ago

PH+POH=14

10+POH=14

POH=4

POH=-LOG(OH-)

OH-= ANTILOG 4=0.0001

Folafoluwa2007
1 year ago

You can solve it without calculator

where PH=10
[H+].[OH-]=10^-14
10^-10.[OH]=10^-14
Divide both side by 10^-10
[OH]=10^-14/10^-10
[OH]= 10^-14+10
[OH]=10^-4mol/dm3

MACCIFO
1 year ago

The calculator that is not even having sin how can you even calculate something wai antilog jamb are so f**king wicked i just pray may the lord help everyone 🙏

darkypearl
11 years ago

how is this calculatd?

Mayorlizz
1 year ago

PH+POH =14
POH=14-10
POH=4
using this formula ,calculate it from the answer the one that will give you 4

p-n/7
1*10^-4
4-1/7
4-0.14
=3.68 ~~ 4✅

OMOYEME1638409182
4 months ago

why is explanation not available

OMOYEME1638409182
3 months ago

Where did u get 10 from

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