If 30cm\(^3\) of oxygen diffuses through porous plug in 7s, how long will it take 60 cm\(^3\) of chlorine to diffuse through the same plug?

djayenimoney

4 years ago

21 is correct.
With practice you'll get used to the formula in no time

Som15432

1 year ago

According to Graham's Law of Diffusion:

Rate of diffusion ∝ 1/√Molecular weight

Since Oxygen (O2) has a molecular weight of 32 and Chlorine (Cl2) has a molecular weight of 70.9:

Rate of diffusion of O2 / Rate of diffusion of Cl2 = √(70.9/32) = √2.215 ≈ 1.487

Now, let's use the given data:

Time taken for 30 cm³ of O2 to diffuse = 7 secs

We need to find the time taken for 60 cm³ of Cl2 to diffuse:

Since the volume of Cl2 is twice that of O2, and the rate of diffusion is 1.487 times slower:

Time taken for 60 cm³ of Cl2 to diffuse ≈ 7 secs × 2 × 1.487 ≈ 20.8 secs = 21 secs

So, it will take 21 secs for 60cm3 of Chlorine to diffuse through the same plug.

Etugo

10 years ago

I don't get this pals, pls help..!

Chiemerie042

4 years ago

14 seconds

Psyrhin

1 year ago

This long procedures won't help in the exam hall.

Som15432

1 year ago

Let Rcl be the rate of difussion of Chlorine and Ro be the rate of diffusion of oxygen
and recall that Graham's law states that: the rate of diffusion is inversely proportional to the square root of it's molar mass
so we have
Ro/Rcl=(√Mcl)/(√Mo)
Ro=30/7,Rcl=60/x,Mcl= 71,Mo= 32
Therefore substituting we have;
(30/7)/(60/x)=(√71)/(√32)
30/7 × X/60 = 1.5
X/14 =1.5
X = 14×1.5
X=21secs
Therefore it will take 21seconds for 60cm3 of Chlorine to diffuse through the porous plug.

Ajisope

8 years ago

I Knw how

Tommyz2009

2 months ago

pls how did they get 760 is it not supposed to be 420

OnyebuchiSuccess

1 year ago

I do not know this question pls

Sebnasseh

1 year ago

how was the 4 used to multiply 30 gotten?

Ajisope

8 years ago

30 of oxygen = 7sec

60 of chlorine = x

T1 = 14

molecular mass of chlorine = 35.5 * 2

molecular mass of oxygen = 16 *2

T2 = T1 square root M2 over M1

then solve