A mixture of 0.20 mole of Ar, 0.20 mole of N2 and 0.30 mole of He exerts a total pressure of 2.1 atm. The partial pressure of He in the mixture is?
a
0.90 atm
b
0.80 atm
c
0.70 atm
d
0.60 atm
Explanation
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Fave.x
1 year ago
total pressure=2.1
total mole=0.7
0.7=2.1
0.3=?
cross multiply
2.1*0.3=0.7?
0.63=0.7?
?=0.63/0.7
?=0.9
A


