2.85g of an oxide of copper gave 2.52g of copper on reduction and 1.90g of another oxide gave 1.52g of copper on reduction. The data above illustrates the law of?
constant composition
conservation of mass
reciprocal proportions
multiple proportions
Explanation
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NOTHING TO STRESS ABOUT IN THIS TYPE OF QUESTION.
NOTE THAT LAW OF DEFINITE PROPORTION AND MULTIPLE PROPORTIONS WORKS HAND IN HAND
1 GET THE PERCENTAGE OF THE METAL IN THE COMPOUND DIFFERENT COMPOUNDS
2 CHECK IF THEY CORRESPONDS ,LIKE IF THE TWO PERCENTAGE ARE APPROXIMATELY THE SAME
3 IF YES, IT'S LAW OF DEFINITE PROPORTION BUT IF THEY'RE NOT EXACTLY THE SAME THOUGH LOOKS A LIKE , IT'S LAW OF MULTIPLE PROPORTION THAT'S OBEY.
WE WERE GIVEN 2.52g OF CU , 2.82g OF CU OXIDE IN THE FIRST EXPERIMENT
SOLVE=
PERCENTAGE OF CU IN CU OXIDE
(2.52/2.82)*100/1=88%
SECOND EXPERIMENT GAVE 1.52g OF CU , 1.9g OF CU OXIDE
SOLVE=(1.52/1.9)*100/1=80%
CONCLUSION>>>>SINCE THEY DIFFERS, THOUGH CLOSE...LAW OF MULTIPLE PROPORTION WAS OBEYED IN THE EXPERIMENT.
FOR MORE CLARIFICATION, SEARCH UNDER THIS TOPIC IN TOPIC BY TOPIC PAST QUESTIONS CALLED JAMB REMIX 
TOPIC:PARTICULATE NATURE OF MATTER. CHEMICAL FORMULA. LAW OF CHEMICAL COMBINATIONS .
The data illustrates the **D. Law of Multiple Proportions**.
The Law of Multiple Proportions states that when two elements combine to form more than one compound, the weights of one element that combine with a fixed weight of the other are in a ratio of small whole numbers.
In this case, copper (Cu) combines with oxygen (O) to form two different oxides. In the first oxide, 2.85g of the compound gives 2.52g of copper, so the weight of oxygen is 2.85g - 2.52g = 0.33g. In the second oxide, 1.90g of the compound gives 1.52g of copper, so the weight of oxygen is 1.90g - 1.52g = 0.38g.
The ratio of the weights of oxygen that combine with a fixed weight of copper in the two compounds is 0.33g : 0.38g, which simplifies to approximately 7:8, a ratio of small whole numbers. This is consistent with the Law of Multiple Proportions.
correct answer A
solution
first what is law of constant or definite proportion?
the law of constant composition states that all pure samples of the same compound contain the same elements combined in the same proportion by mass
sample x 2.85g gave 2.52g on reduction
sample y 1.90g gave 1.52g on reduction
ratio of oxide/copper=
2.52/2.85=0.88 of sample x
1.52/1.90=0.8 of sample y
divide by the smallest value which is 0.8
0.88/0.8=1
0.8/0.8=1
they are combined in the same proportion by mass i.e 1:1
hence the correct answer is A
The correct answer is D.
Explanation:
The given data provides information about the reduction of two different copper oxides. Let's analyze the data:
First oxide:
Mass of the first oxide = 2.85g
Mass of copper obtained = 2.52g
Mass of oxygen = 2.85g - 2.52g = 0.33g
Second oxide:
Mass of the second oxide = 1.90g
Mass of copper obtained = 1.52g
Mass of oxygen = 1.90g - 1.52g = 0.38g
Now, let's compare the ratios of masses of copper and oxygen in both oxides:
First oxide:
2.52
0.33
โ
7.64
Second oxide:
1.52
0.38
โ
4
Since the ratio of the masses of copper and oxygen in the two oxides is approximately 2:1 (7.64 รท 4 โ 2), this illustrates the Law of Multiple Proportions. This law states that when two elements combine to form more than one compound, the masses of one element that combine with a fixed mass of the other element are in simple ratios.
