Two cylinders A and B each contains 30 cm\(^3\) of oxygen and nitrogen respectively at the same temperature and pressure. If there are 5.0 moles of nitrogen, then the mass of oxygen is?
3.2 g
6.4 g
80.0 g
160.0 g
Explanation
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since they both have the same
vol,temp,nd pressure it means
avogadro's law is being obeyed
which means they will have the
same number of moles
Since the mass of oxygen gas is 32g
5*32=160

n=m/M
M=2×14=28
m=5×28
m=28
N2+O2 -------- 2NO
28g --------- 140g
32g -------- 140÷32/28 = 160g

the correct answer is 80g...
since they both have the same vol,temp,nd pressure it means avogadro's law is being obeyed which means they will have the same number of moles
so mass of oxygen =no of moles x molar mass which is 5x16=80g

