What volume of oxygen will remain after reacting 8cm\(^3\) of hydrogen with 20cm\(^3\) of oxygen?
10 cm3
12 cm3
14 cm3
16 cm3
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It's simple if you understand stoichiometry.
The equation of the reaction is
H2 + O2 -----> H2O
Balance the equation
2H2 + O2 ----> 2H2O
2moles of H2 requires 1mole of O2.
2cm³ of H2 requires 1cm³ of O2.
From the question, 8cm³ of Hydrogen reacted with 20cm² of O2.
We have to find the actual amount of O2 that will react 8cm³ of H2.
If 2cm³ of H2 requires 1 cm of O2.
8cm³ of H2 will require xcm of O2.
2.......1
8.......x
cross multiplying,
2 × x = 1 × 8
x = 8/2 =4cm³ of O2.
2H2 + O2--------> 2H2O
2. 1. 2
8. 20
8. 4
.....,...............
0. 16
.: The vol of oxygen remaining after the
reaction is 16
Option D
3What volume of oxygen will remain after reacting 8cm3of hydrogen with 20cm3of oxygen? A.10 cm3 B.12 cm3 C.14 cm3 D.16 cm3Correct Answer: Option D
