What volume of oxygen will remain after reacting 8cm\(^3\) of hydrogen with 20cm\(^3\) of oxygen?
First write a balanced equation for the chemical reaction:
2H\(_2\) + O\(_2\) → 2H\(_2\)O
Mole ratio: 2 moles : 1 mole
Expected reacted volume: 8 cm\(^3\) : 20 cm\(^3\)
Actual reacted volume: 8 cm\(^3\) : 4 cm\(^3\)
Residual Volume(Expected - Actual): 0 : 16 cm\(^3\)
Therefore, the volume of oxygen remaining is 16 cm\(^3\)
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