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The number of hydrogen ions in 4.9 g of tetraoxosulphate (IV) acid is? (S =...

Chemistry
JAMB 1995

The number of hydrogen ions in 4.9 g of tetraoxosulphate (IV) acid is?

(S = 32, O =16, H = 1, Avogadro Number = 6.02 x 10\(^{23}\) )

  • A. 3.01 x 1022
  • B. 6.02 x 1022
  • C. 3.01 x 1023
  • D. 6.01 x 1023
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Correct Answer: Option B
Explanation

First write a dissociation equation:   H\(_2\)SO\(_4\)  ⇌  2H\(^+\)  +  SO\(_4\)\(^{2-}\)

Number of moles = \(\frac{Number of ions}{Avogadro number}\)

But we need to get the number of moles first by applying  n = \(\frac{m}{M}\)

                                                                                            n = \(\frac{4.9}{98}\) (Molar mass of H\(_2\)SO\(_4\) = 98g/mol)

                                                                                            n = 0.05 mole

Number of moles = \(\frac{Number of ions}{Avogadro number}\)

Number of hydrogen ions = ( n x L ) X 2 → We multiplied by 2 because 2H\(^+\) were formed.

                                         = 0.05 x 2 x 6.02 x 10\(^{23}\)

                                         = 6.02 x 10\(^{22}\) ions


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