The number of hydrogen ions in 4.9 g of tetraoxosulphate (IV) acid is?
(S = 32, O =16, H = 1, Avogadro Number = 6.02 x 10\(^{23}\) )
First write a dissociation equation: H\(_2\)SO\(_4\) ⇌ 2H\(^+\) + SO\(_4\)\(^{2-}\)
Number of moles = \(\frac{Number of ions}{Avogadro number}\)
But we need to get the number of moles first by applying n = \(\frac{m}{M}\)
n = \(\frac{4.9}{98}\) (Molar mass of H\(_2\)SO\(_4\) = 98g/mol)
n = 0.05 mole
Number of moles = \(\frac{Number of ions}{Avogadro number}\)
Number of hydrogen ions = ( n x L ) X 2 → We multiplied by 2 because 2H\(^+\) were formed.
= 0.05 x 2 x 6.02 x 10\(^{23}\)
= 6.02 x 10\(^{22}\) ions
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