What volume of Oxygen measured at s.t.p would be liberated on electrolysis by 9650 coulombs of electricity?
(Molar volume of gas = 22.4 dm\(^3\), 1F = 96,500 C/mol)
a
22.4 dm3
b
11.2 dm3
c
1.12 dm3
d
0.560 dm3
Explanation
Correct Option
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DBRANDY
11 years ago
2OH -- 1/2 O2 + H2O + 2e^- ( equation of reaction) if 1 mole deposited 1F therefore 0.1 mole will deposit 0.1 F. In equation of reaction 2 F liberated 1/2 ( or 0.5) mole of oxygen therefore 0.1 F = 0.1/2 × 0.5 = 0.025 mole. So if 1 mole = 22.4dm^3 therefore 0.025 mole = 0.025/1 × 22.4 = 0.560 dm^3 option D.
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