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What volume of Oxygen measured at s.t.p would be liberated on electrolysis by 9650 coulombs...

Chemistry
JAMB 1994

What volume of Oxygen measured at s.t.p would be liberated on electrolysis by 9650 coulombs of electricity?
(Molar volume of gas = 22.4 dm\(^3\), 1F = 96,500 C/mol)

  • A. 22.4 dm3
  • B. 11.2 dm3
  • C. 1.12 dm3
  • D. 0.560 dm3
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Correct Answer: Option D
Explanation

For a diatomic divalent element like oxygen, the following reaction takes place:

              2H\(_2\)0  →  O\(_2\)  +  4H\(^+\) +  4e\(^-\)

⇒  4e\(^-\) are transferred to liberate 1 mole of O\(_2\)

So, to calculate the volume of O\(_2\)

4 Faradays (4 x 96,500) of electricity to produce 22.4 dm\(^3\) of O\(_2\) at S.T.P

    4 X 96,500 C = 22.4 dm\(^3\)

      9650 C  =  x dm\(^3\)

    x = \(\frac{9650 X 22.4}{ 4 X  96,500}\)

    x = 0.56dm\(^3\)

 


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