Correct Answer: Option C

Explanation

Given:

V\(_A\) = 20cm\(^3\);  C\(_A\) = 2.0M; C\(_B\) = 0.05M; V\(_B\) = ?

      CH\(_3\)COOH    +    NaOH  →   CH\(_3\)COONa  +  H\(_2\)O 

               1 mole                    :                   1 mole

n = \(\frac{CV}{1000}\)

   = \(\frac{{2}\times{20}}{1000}\)

n = 0.04 mole                        :                  0.04 mole

                                                   But n = \(\frac{mass}{Molar Mass}\)

                                                        m = n x M

                                                            = 0.04 x 82 

                                               mass    = 3.28g 

Therefore, the mass of the salt is 3.28g

N.B: 82 is the Molar mass of the salt, CH\(_3\)COONa = 12 + (1 x 3) + 12 + 16 + 16 + 23 = 82g/mol

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