The solubility, in moles per dm3 of 20.2 g of potassium trioxonitrate (V) dissolve in 100 g of the resulting mixture is?

(K = 39, O = 16, N =14).

prezzyfc51.com

5 years ago

Generally, Solubility=solute/solvent× 1000/molar mass
Solute= 20.2g
Solvent=100g
Molar mass of potassium trioxonitrate(v) >>>>>kno3
== (39+14+[16×3])
= (39+14+48)
=101
Solubility = 20.2/100 × 1000/101
=20200/10100
=2. 00
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datgirlmimi

4 years ago

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datgirlmimi

4 years ago

Swr!

Silveradero

1 year ago

OR a simpler method
Solubility in moldm-3=mass×standard volume÷molarmass×volume

Now remember 1gof density =1cm3 of volume

So....mass=20.2g, volume=100g=100cm3, standard volume=1000, mm=KNO3=39+14+[16×3]=101

Therfore, Solubility = 20.2×1000÷101×100
20200÷10100 = 2

Therefore Solubilty in moldm/3 = 2moldm/3

Ahmad008

3 months ago

i need calculator please.

Gozzyfunds

1 year ago

why is there no explanation