The solubility, in moles per dm3 of 20.2 g of potassium trioxonitrate (V) dissolve in 100 g of the resulting mixture is?
(K = 39, O = 16, N =14).
Given:
Mass of KNO\(_3\) = 20.2g
Volume of solvent = 100g
Molar Mass of KNO\(_3\) = 39 + 14 + (16 x 3) = 101g/mol
Solubility = \(\frac{mass}{Molar mass}\) X \(\frac{1000}{Volume of solvent}\)
= \(\frac{20.2}{101}\) X \(\frac{1000}{100}\)
= 2.00 moldm\(^{-3}\)
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