To what temperature must a gas 273 K be heated in order to double both its volume and pressure?

ezicool8

11 years ago

p1=p v1=v T1=273k

P2=2p v2=2v T2=?

By general gas law p1v1/T1=p2v2/T2

T2=2*p*2*v*273

---------------- =4*273=1092k

P*V

Bolalanle

5 years ago

There are no explanation in all most all the questions I have been checking

Hopequdus

5 years ago

Using the general gas law formula
P1V1/T1=P2V2/T2
Since it has been stated that both the volume and pressure are double.
See the image below for it solution

Afoo760

1 year ago

No correction

Jaykaybabs

7 years ago

PiVi/Ti=P2V2/T2
Pi--1atm
p2---2atm
Vi----22.4
v2----44.8
Ti---290
T2?
substitute
2×44.8×290/1×22.4=1160