Correct Answer: Option D

Explanation

Given:

T\(_1\) = 273K       V\(_1\) = X         P\(_1\) = Y  → Let x and y represent the initial volume and initial pressure respectively.

T\(_2\) = ?             V\(_2\) = 2X       P\(_2\) = 2Y   → Since the volume and pressure were doubled.

Using the formula, \(\frac{P_1 V_1}{T_1}\) =  \(\frac{P_2 V_2}{T_2}\)

                            T\(_2\) =  \(\frac{P_2 V_2 T_1}{P_1 V_1}\)

                                 = \(\frac{2Y\times 2X \times 273}{Y\times X}\)

                                 = 2 X 2 X 273

                          T\(_2\)= 1092K

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