8g CH4 occupies 11.2 dm3 at s.t.p. What volume would 22 g of CH3CH2CH3 occupy under the same condition?

(C = 12, H = 1)

Ogbonna_Chisom

3 years ago

Molar mass of methane = 16g/mol

At S.T.P. 16g occupies 22.4dm3
So 8g will occupy 11.2dm3



Molar mass of propane = 44g/mol−1
At S.T.P. 44g occupies 22.4dm3
So 22g will occupy 11.2dm3

Shekheenah

11 years ago

How?

Joshua2003c

6 years ago

How??

Asebioyo

2 years ago

Pls I need an explanation to this question

annalice

3 years ago

the molar mass for ethane is 30
so
30=22.4
22=x
x=22.4×22/30=16 the answer isn't there guys

TASHAKAYLA

1 year ago

Video explanation

FELICIA OKEKE

13 years ago

according to avogadro's law

peter samson

9 years ago

yeah volume of all the gases(in the same condition)..contains the same number of molecule=11.2