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8g CH4 occupies 11.2 dm3 at s.t.p. What volume would 22 g of CH3CH2CH3 occupy...

Chemistry
JAMB 1994

8g CH4 occupies 11.2 dm3 at s.t.p. What volume would 22 g of CH3CH2CH3 occupy under the same condition?

(C = 12, H = 1)

  • A. 3.7 dm3
  • B. 11.2 dm3
  • C. 22.4 dm3
  • D. 33.6 dm3
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Correct Answer: Option B
Explanation

1 mole of any gas has a volume of 22.4dm3 at STP,  SO 1mole of propane = 44g = 22.4dm3

                                                                                                                              22g = ?

 ( 22 x 22.4)/ 44 = 11.2dm3

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