When dilute aqueous solutions of lead (II) nitrate and potassium bromide are mixed, a precipitate is observed.
The products of this reaction are?
a
PbO(s) + Br- + KNO3
b
Br2 + NO2(g) + PbBr2(s)
c
PbO(s) + K+(aq) + Br(aq) + NO2(g)
d
PbBr2(s) + K(aq) + K+(aq) + NO3(aq)
Explanation
Correct Option
dNo explanation available
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Som15432
1 year ago
The correct answer is:
D. PbBr2(s) + K+(aq) +K(aq) + NO3-(aq)
When dilute aqueous solutions of lead(II) nitrate (Pb(NO3)2) and potassium bromide (KBr) are mixed, a precipitate of lead(II) bromide (PbBr2) is formed:
Pb(NO3)2(aq) + 2KBr(aq) → PbBr2(s) + 2KNO3(aq)
The products of this reaction are:
- Lead(II) bromide (PbBr2) as a precipitate
- Potassium ions (K+) in aqueous solution
- Nitrate ions (NO3-) in aqueous solution
