The standard enthalpies of formation of CO_2(g), H₂O(g) and CO_(g) in kJ mol^- are -394, -242 and -110 respectively. What is the standard enthalpy change for the reaction CO_(g) + H_2(g)O → CO_2(g) + H_2(g)?

-42 KJ mol^-

+42 KJ mol^-

-262 KJ mol^-

+262 KJ mol^-

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Edebo20

2 years ago

∆H = Hp - Hr
Hp = -394
Hr= -242-110
∆H = -394-(-352)
∆H = -394 + 352 = -42

vickyf

9 years ago

d ans is correct-42

misNora

2 months ago

-242-110=-352
-394+352=-42kj

biganimal

2 years ago

Gia.ikl

3 years ago

can someone please explain?

Dave333

4 years ago

I got C as my answer

walex15

11 years ago

Wrong ansa, d correct ansa is (b)...heat of reactants - heat of product (-110+(-242))-(-342) --- +42kj

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The standard enthalpies of formation of CO2(g), H2O(g) and CO(g) in kJ mol- are -394, -242 and -110 respectively. What is the standard enthalpy change for the reaction CO(g) + H2(g)O → CO2(g) + H2(g)?

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The standard enthalpies of formation of CO_2(g), H₂O(g) and CO_(g) in kJ mol^- are -394, -242 and -110 respectively. What is the standard enthalpy change for the reaction CO_(g) + H_2(g)O → CO_2(g) + H_2(g)?