During the electrolysis of a salt of a metal M, a current of 0.5 A flows from for 32 minutes 10 seconds and deposits 0.325 g of M, What is the charge of the metal ion?
(M = 65, If = 96,500 C per mole of electron)
a
1
b
2
c
3
d
4
Explanation
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vickyf
9 years ago
no. of moles ×no.of ion×faraday=i(current)×t(time).....
0.325/65×no. of ion×96500=0.5×((32×60)+10).....
0.005×no. of ion×96500=965..........
no. of ion×482.5=965......
no.of ion=965÷482.5....=2.......





