An organic compound containing 40.1% carbon and 6.6% hydrogen has an empirical formula of?

SeanRaph

2 months ago

40.1% Carbon
6.6% Hydrogen.
Atomic Mass of Carbon = 12
Atomic mass of hydrogen= 1

40.1/12 6.6/1
3.3 6.6
divide through by the lowest
3.3/3.3 =1
6.6/3.3 = 2 …; CH2

Now you may be wondering where Oxygen came from🌝
just add your given percentage 40.1+6.6 =100-46.7=53.3now this is ur percentage of oxygen🥱
from our calculations earlier do same for oxygen 53.3/16 =3.3

(C)
3.3/3.3= 1
(H)
6.6/3.3= 2
(O)
3.3/3.3 =1

that is🥱...CH2O
it's not supposed to be long just taking my time since nobody dropped a comment🥱🏃‍♂️😂😂😂😂